13[3-(2-2x)]+6x=4(8x+4)-3

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Solution for 13[3-(2-2x)]+6x=4(8x+4)-3 equation:


Simplifying
13[3 + -1(2 + -2x)] + 6x = 4(8x + 4) + -3
13[3 + (2 * -1 + -2x * -1)] + 6x = 4(8x + 4) + -3
13[3 + (-2 + 2x)] + 6x = 4(8x + 4) + -3

Combine like terms: 3 + -2 = 1
13[1 + 2x] + 6x = 4(8x + 4) + -3
[1 * 13 + 2x * 13] + 6x = 4(8x + 4) + -3
[13 + 26x] + 6x = 4(8x + 4) + -3

Combine like terms: 26x + 6x = 32x
13 + 32x = 4(8x + 4) + -3

Reorder the terms:
13 + 32x = 4(4 + 8x) + -3
13 + 32x = (4 * 4 + 8x * 4) + -3
13 + 32x = (16 + 32x) + -3

Reorder the terms:
13 + 32x = 16 + -3 + 32x

Combine like terms: 16 + -3 = 13
13 + 32x = 13 + 32x

Add '-13' to each side of the equation.
13 + -13 + 32x = 13 + -13 + 32x

Combine like terms: 13 + -13 = 0
0 + 32x = 13 + -13 + 32x
32x = 13 + -13 + 32x

Combine like terms: 13 + -13 = 0
32x = 0 + 32x
32x = 32x

Add '-32x' to each side of the equation.
32x + -32x = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 32x + -32x

Combine like terms: 32x + -32x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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